Assumptions On Definability Over The Standard Model Ω, Part 2

So we set out the basic assumptions about definability over \Omega that factor into the proof of Tarski’s theorem.  Let’s go over each one to get clear on all the definitions.

(i) Every effectively computable function \textup{F}: \omega \rightarrow \omega is definable over \Omega.

A function \textup{F}: \textup{X} \rightarrow \textup{Z} is effectively computable if, and only if, there is an effective procedure such that, for any x \in \textup{X} the procedure calculates the value \textup{F}(x).  The claim is that every such function defined on the natural numbers is definable in the standard model.

(ii) Every decidable set \textup{X} \subseteq \omega is definable over \Omega.

A subset \textup{A} \subseteq \textup{X} is decidable if, and only if, the property \mathcal{P} defined as (\mathcal{P}(x): \Longleftrightarrow x \in \textup{A}) is decidable in \textup{X}.  And a property \mathcal{P} defined over a set \textup{X} is decidable in \textup{X} if, and only if, there is an effective (or decision) procedure for deciding, for any x \in \textup{X} whether or not \mathcal{P}(x) holds.  Here the claim is straightforward, every such set of natural numbers is definable in the standard model.

(iii) Every effectively countable set \textup{X} \subseteq \omega is definable over \Omega

Finally, a set \textup{X} is effectively countable if, and only if, \textup{X} is empty or there is an effectively computable function \textup{F}: \omega \rightarrow \textup{X} that counts \textup{X} (i.e., \textup{X} is the image of \textup{F}, \textup{X} = \mathsf{Im}(\textup{F}) := \{\textup{F}(n): n \in \omega\}). So, what’s being assumed here is that the effectively countable subsets of the natural numbers are definable in the standard model.

Just a few more definitions and we can get into Tarski’s theorem.  In the next update I’ll define the set of indices for the theorems of \Omega as well as a diagonalization function that will play a role in the proof.

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